#### Answer

0.250 L of concentrated hydrocloric acid (12.0M)

#### Work Step by Step

1. Find the necessary volume:
$C_1 * V_1 = C_2 * V_2$
$ 1.50M * 2.00L= 12.0M * V_2$
$ 3.00M*L = 12.0M * V_2$
$V_2 = \frac{3.00M*L}{12.0M}$
$V_2 = 0.250 L$

Chegg costs money, GradeSaver solutions are free!

Published by
Brooks/Cole Publishing Co.

ISBN 10:
1133610668

ISBN 13:
978-1-13361-066-3

0.250 L of concentrated hydrocloric acid (12.0M)

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.