#### Answer

0.250 L of concentrated hydrocloric acid (12.0M)

#### Work Step by Step

1. Find the necessary volume:
$C_1 * V_1 = C_2 * V_2$
$ 1.50M * 2.00L= 12.0M * V_2$
$ 3.00M*L = 12.0M * V_2$
$V_2 = \frac{3.00M*L}{12.0M}$
$V_2 = 0.250 L$

Published by
Brooks/Cole Publishing Co.

ISBN 10:
1133610668

ISBN 13:
978-1-13361-066-3

0.250 L of concentrated hydrocloric acid (12.0M)

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