## Chemistry 10th Edition

1. Write the unbalanced equation. - Calcium (Ca) reacts with carbon (C) to produce calcium carbide: $(CaC_2)$ $$Ca + C \longrightarrow CaC_2$$ 2. Balance the equation. $$Ca+2C\longrightarrow CaC_2$$ - We just need to balance the number of carbon atoms, by putting 2 as the coefficient for $C$ in the reactants. 3. $C$ : 12.01 g/mol $$\frac{1 \space mol \space C }{ 12.01 \space g \space C } \space and \space \frac{ 12.01 \space g \space C }{1 \space mol \space C }$$ $Ca$ : 40.08 g/mol $$\frac{1 \space mol \space Ca }{ 40.08 \space g \space Ca } \space and \space \frac{ 40.08 \space g \space Ca }{1 \space mol \space Ca }$$ $$1.885 \space g \space C \times \frac{1 \space mol \space C }{ 12.01 \space g \space C } \times \frac{ 1 \space mol \space Ca }{ 2 \space mol \space C } \times \frac{ 40.08 \space g \space Ca }{1 \space mol \space Ca } = 3.145 \space g \space Ca$$