Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - STP, Standard Molar Volume, and Gas Densities: 37

Answer

0.11 mole molecules or 6.62$\times10^{22}$ molecules approximately.

Work Step by Step

At STP, $\frac{V}{n}$ is always equal to 22.4 L$mol^{-1}$. This gives, Number of moles, n= $\frac{V}{22.4Lmol^{-1}}$= $\frac{2.50L}{22.4Lmol^{-1}}$ $\approx$ 0.11 mole molecules or 0.11$\times$$6.022\times10^{22}$ molecules.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.