Fundamentals of Biochemistry: Life at the Molecular Level 5th Edition

Published by Wiley
ISBN 10: 1118918401
ISBN 13: 978-1-11891-840-1

Chapter 10 - Membrane Transport - Exercises - Page 318: 1


-1265.66 J.K$^{-1}$.Mol$^{-1}$

Work Step by Step

The free energy $\Delta$G is calculated using the following formula: $\Delta$G = RTIn $\frac{[Glucose]in}{[Glucose]out}$, where $\Delta$G is free energy. R = 8.3145 J.K$^{-1}$.Mol$^{-1}$ T = 298K There is a conversion factor of 1mM = 0.001M Now, plug all of these elements into the original equation. $\Delta$G = (8.3145J.K$^{-1}$.Mol$^{-1}$(298)In$\frac{0.003}{0.005}$ $\Delta$G = (8.3145J.K$^{-1}$.Mol$^{-1}$(298)In(0.6) $\Delta$G = (8.3145J.K$^{-1}$.Mol$^{-1}$(298)(-0.51082) = -1265.66 J.K$^{-1}$.Mol$^{-1}$
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