Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 Applications of Vectors - 7.5 Exercises - Page 342: 3

Answer

$0.71$

Work Step by Step

From the given figure, note that $|v|=1$ and $\theta=45^\circ$. The horizontal component a of a vector $v$ having magnitude |v| and direction angle $\theta $ is given by $$a =|v| \cos \theta$$ $$a =(1) \cos 45^\circ =\frac{1}{\sqrt {2}}=\frac{\sqrt 2}{2}\approx 0.71 $$ Therefore, the horizontal component, $a$, of vector $v$ is $0.71$.
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