Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.2 The Ambiguous Case of the Law of Sines - 7.2 Exercises - Page 310: 12

Answer

$B = 30^{\circ}$

Work Step by Step

We can use the law of sines to find the angle $B$: $\frac{a}{sin~A} = \frac{b}{sin~B}$ $sin~B = \frac{b~sin~A}{a}$ $sin~B = \frac{(3)~sin~(45^{\circ})}{3\sqrt{2}}$ $sin~B = \frac{(3)~(\frac{\sqrt{2}}{2})}{3\sqrt{2}}$ $sin~B = \frac{1}{2}$ $B = arcsin(\frac{1}{2})$ $B = 30^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.