#### Answer

The amplitude is $2$, the period is $2\pi$, there is no vertical translation and the phase shift is $\pi$ to the left since $d$ is less than zero.

#### Work Step by Step

We first write the equation in the form $y=c+a \sin [b(x-d)]$. Therefore, $y=2\sin (x+\pi)$ becomes $y=0+2\sin [1(x+\pi)]$.
Comparing the two equations, $a=2,b=1$,c=0 and $d=-\pi$.
The amplitude is $|a|=|2|=2.$
The period is $\frac{2\pi}{b}=\frac{2\pi}{1}=2\pi$.
The vertical translation is $c=0$.
The phase shift is $|d|=|-\pi|=\pi$
Therefore, the amplitude is $2$, the period is $2\pi$, there is no vertical translation and the phase shift is $\pi$ to the left since $d$ is less than zero.