Trigonometry (11th Edition) Clone

about $81.6^{o}$
Arc length s (for central angle $\theta$):$\quad s=r\theta$, where $\theta$ is in radians Converting between Degrees and Radians 1. Multiply a degree measure by $\displaystyle \frac{\pi}{180}$ radian and simplify to convert to radians. 2. Multiply a radian measure by $\displaystyle \frac{180^{\mathrm{o}}}{\pi}$ and simplify to convert to degrees. ---------------- For the smaller gear, the length of the arc that turns is $s=r\theta$ $\theta=150^{o}$ needs to be converted to radians (case 1): $s=r\displaystyle \cdot 150\cdot\frac{\pi}{180}=6.84\cdot 150\cdot\frac{\pi}{180}=\frac{6.84\cdot 5\cdot\pi}{6}$ The bigger gear rotates for the same arc length, so $s=r\theta\qquad$ ( ... solve for $\theta$) $\displaystyle \frac{6.84\cdot 5\cdot\pi}{6}=12.46\theta$ $\displaystyle \theta=\frac{6.84\cdot 5\cdot\pi}{6\cdot 12.46} \qquad$(...radians to degrees ...) $\displaystyle \theta=\frac{6.84\cdot 5\cdot\pi}{6\cdot 12.46}\cdot\frac{180^{\mathrm{o}}}{\pi}=\frac{6.84\cdot 5\cdot 30^{o}}{12.46}\approx$81.568471337$6^{o}$ The larger gear rotates for about $81.6^{o}.$