Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Cumulative Review - Page 694: 6



Work Step by Step

$2\frac{1}{3}+4\frac{2}{5}+3$ $=2\frac{5}{15}+4\frac{6}{15}+3\frac{0}{15}$ $=9\frac{11}{15}$
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