#### Answer

$3$

#### Work Step by Step

$\frac{\frac{7}{6}+\frac{2}{3}}{\frac{3}{2}-\frac{8}{9}}$
$=(\frac{7}{6}+\frac{2}{3})\div(\frac{3}{2}-\frac{8}{9})$
$=(\frac{7}{6}+\frac{4}{6})\div(\frac{27}{18}-\frac{16}{18})$
$=\frac{11}{6}\div\frac{11}{18}$
$=\frac{11}{6}\times\frac{18}{11}$
$=\frac{1}{1}\times\frac{3}{1}$
$=3$