Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 283: 4

Answer

$1\frac{1}{2}$

Work Step by Step

$\frac{\frac{9}{25}}{\frac{6}{25}}$ $=\frac{9}{25}\div\frac{6}{25}$ $=\frac{9}{2̶5̶}\times\frac{2̶5̶}{6}$ $=\frac{9}{6}$ $=\frac{3}{2}$ $=1\frac{1}{2}$
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