Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 283: 3

Answer

$\frac{7}{3}=2\frac{1}{3}$

Work Step by Step

$\frac{2}{3}\div\frac{2}{7}=\frac{2}{3}\times\frac{7}{2}=\frac{/\!\!2\times7}{3\times/\!\!2}=\frac{7}{3}$
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