Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 4 - Calculating the Derivative - 4.2 Derivatives of Products and Quotients - 4.2 Exercises: 10

Answer

\[{q^,}\,\left( x \right) = - 24{x^{ - 7}} + 28{x^{ - 8}} - 9{x^{ - 4}} + 12{x^{ - 5}}\]

Work Step by Step

\[\begin{gathered} q\,\left( x \right) = \,\left( {{x^{ - 2}} - {x^{ - 3}}} \right)\,\left( {3{x^{ - 1}} + 4{x^{ - 4}}} \right) \hfill \\ Use\,\,the\,\,product\,\,rule\,\,to\,\,find\,\,q{\,^,}\left( x \right) \hfill \\ q{\,^,}\left( x \right) = \,\left( {{x^{ - 2}} - {x^{ - 3}}} \right)\,{\left( {3{x^{ - 1}} + 4{x^{ - 4}}} \right)^,} + \,\left( {3{x^{ - 1}} + 4{x^{ - 4}}} \right)\,\left( {{x^{ - 2}} - {x^{ - 3}}} \right) \hfill \\ Then \hfill \\ {q^,}\,\left( x \right) = \left( {{x^{ - 2}} - {x^{ - 3}}} \right)\,\,\left( { - 3{x^{ - 2}} - 16{x^{ - 5}}} \right) + \,\left( {3{x^{ - 1}} + 4{x^{ - 4}}} \right)\,\left( { - 2{x^{ - 3}} + 3{x^{ - 4}}} \right) \hfill \\ Simplify\,\,by\,\,multiplying\,\,and\,\,combining\,\,terms \hfill \\ {q^,}\,\left( x \right) = - 3{x^{ - 4}} - 16{x^{ - 7}} + 3{x^{ - 5}} + 16{x^{ - 8}} - 6{x^{ - 4}} + 9{x^{ - 5}} - 8{x^{ - 7}} + 12{x^{ - 8}} \hfill \\ {q^,}\,\left( x \right) = - 24{x^{ - 7}} + 28{x^{ - 8}} - 9{x^{ - 4}} + 12{x^{ - 5}} \hfill \\ \hfill \\ \end{gathered} \]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.