Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 5 - Accumulating Change: Limits of Sums and the Definite Integral - Review Activities - Page 415: 20

Answer

$$\frac{1.4^{x}}{\ln(1.4)}-\cos x-\frac{8}{5}\ln x +c$$

Work Step by Step

Given $$ \int\left(1.4^{x}+\sin x-\frac{8}{5 x}\right) d x $$ Thus: \begin{align*} \int\left(1.4^{x}+\sin x-\frac{8}{5 x}\right) d x&=\frac{1.4^{x}}{\ln(1.4)}-\cos x-\frac{8}{5}\ln x +c\end{align*}
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