Answer
$8.17x^4+1.9x^2-15x+C$
Work Step by Step
$\int(32.68x^3+3.8x-15)dx=\int(32.68x^3)dx+\int(3.8x)dx-\int(15)dx=\frac{32.68x^{(3+1)}}{3+1}+\frac{3.8x^{(1+1)}}{1+1}-\frac{15x^{0+1}}{0+1}+C=8.17x^4+1.9x^2-15x+C$
Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition
by LaTorre, Donald R.; Kenelly, John W.; Reed, Iris B.; Carpenter, Laurel R.; Harris, Cynthia R.
Published by
Brooks Cole
ISBN 10:
1-43904-957-2
ISBN 13:
978-1-43904-957-0
Chapter 5 - Accumulating Change: Limits of Sums and the Definite Integral - 5.5 Activities - Page 373: 4
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