Answer
$k'(x)=3.7e^x -\frac{2}{x}$
Work Step by Step
We solve this problem by implementing the derivative rule for natural log functions $\frac{d}{dx}(lnx)=\frac{1}{x}$. And since $f(x)=e^x$ is equal to $f'(x)=e^x$ then $3.7e^x$ stays the same.
Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition
by LaTorre, Donald R.; Kenelly, John W.; Reed, Iris B.; Carpenter, Laurel R.; Harris, Cynthia R.
Published by
Brooks Cole
ISBN 10:
1-43904-957-2
ISBN 13:
978-1-43904-957-0
Chapter 3 - Determining Change: Derivatives - 3.2 Activities - Page 209: 14
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