Answer
Verified
Work Step by Step
$\frac{df}{dx}=\lim\limits_{h\to 0}\frac{f(x+h)-f(x)}{h}$
$=\lim\limits_{h\to 0}\frac{-3(x+h)^2-5(x+h)-(-3x^2-5x)}{h}=\lim\limits_{h\to 0}\frac{-3h^2-6xh-5h}{h} = 0-6x-5=-6x-5$
Hence Verified.
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