## Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole

# Chapter 1 - Ingredients of Change: Functions and Limits - 1.3 Activities - Page 31: 32

#### Answer

$6$

#### Work Step by Step

$\lim\limits_{h \to 0}\frac{(h+3)^2-3^2}{h}=\lim\limits_{h \to 0}\frac{6h+h^2}{h}=\lim\limits_{h \to 0}(6+h)=6$

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