#### Answer

Divergent

#### Work Step by Step

$\Sigma \frac{1}{nln(n)}$
$\lim\limits_{t \to \infty}\int_{1}^{t}\frac{1}{xln(x)}=\lim\limits_{t \to \infty}[ln(ln(x))]^{t}_{1}=ln(ln(\infty))-ln(ln(2)=\infty$
Divergent

Published by
Cengage

ISBN 10:
1285740629

ISBN 13:
978-1-28574-062-1

Divergent

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.