Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.3 Volumes of Revolution - Exercises - Page 304: 12



Work Step by Step

The volume is given by $$ \pi \int_{0}^{\pi / 2}\left(\sqrt{\cos x \sin x)^{2}} d x=\pi \int_{0}^{\pi / 2}(\cos x \sin x) d x\\=\frac{\pi}{2} \int_{0}^{\pi / 2} \sin 2 x d x=\left.\frac{\pi}{4}(-\cos 2 x)\right|_{0} ^{\pi / 2}=\frac{\pi}{2}\right. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.