Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 11 - Section 11.3 - The Integral Test and Estimates of Sums - 11.3 Exercises - Page 758: 6

Answer

Convergent

Work Step by Step

$\sum_{n=1}^{\infty} \frac{1}{(5n-1)^4}$ Before applying the Intergal Test, we need to ensure that $f(n)$ is decreasing, let $f(x)=\frac{1}{(5x-1)^4}\implies f'(x)=-\frac{1}{20}\frac{1}{(5x-1)^5}$ Above equation implies that $f(x)$ is decreasing if $x>\frac{1}{5}$ Now by apply theIntegral Test, we have: $\int_{1}^{\infty}\frac{1}{(5x-1)^4}=\lim_{t\to\infty}\int_{1}^{t}\frac{1}{(5x-1)^4}=-\frac{1}{15}\lim_{t\to\infty}\biggl[\frac{1}{(5x-1)^3}\biggr]_{1}^{t}=\frac{1}{960}$ Since the integral is convergent, the series is also convergent by Integral Test.
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