Answer
$log_{7}\frac{x+9}{ x^{2}+10}$
Work Step by Step
The quotient property of logarithms tells us that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$).
Therefore, $log_{7}(x+9)-log_{7}(x^{2}+10)= log_{7}\frac{x+9}{ x^{2}+10}$.
