Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 6 - Linear Transformations - 6.1 Definition of a Linear Transformation - Problems - Page 389: 9

Answer

See below.

Work Step by Step

Let $x=2$ and $y=3$, then $T(x+y)=T(5)=a+b+c+1$. But $T(x)=a+b+c+1$ and $T(y)=a+b+c+1$, thus $T(x)+T(y)=2(a+b+c+1)\ne a+b+c+1=T(x+y)$.
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