College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Prologue: Principles of Problem Solving - Problems - Page 4: 4


$57$ minutes

Work Step by Step

The algebraic solution is to figure out how many amoeba can fit in the container. The amoeba splits into two every three minutes, so we can define the amount of amoeba in the tank as $f(x)=2^{x}$, where $x$ is the amount of three minute intervals. One hour has $20$-three minute periods, so we get $f(20)=2^{20}=1048576$ amoeba. Now, if two amoeba are placed, we have to change the function to show double the amount of amoeba. We set the function as $f(x)=2*2^{x}=2^{x+1}$ where $x$ is the amount of three minute intervals. We now solve for $x$ in the equation $f(x)=1048576=2^{x+1}$. We have said that $1048576=2^{20}$, substituting this into the equation yields $2^{20}=2^{x+1}$. This means that $20=x+1$, and $x=19$. Since there are $19$-three minute periods, there is a total of $19*3$, or $57$ minutes.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.