College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 3, Polynomial and Rational Functions - Chapter 3 Review - Exercises - Page 357: 53

Answer

$P(x)=4x^3 - 18 x^2 + 14 x + 12$.

Work Step by Step

The factor theorem says that if $f(c)=0$, then $(x-c)$ is a factor of $f(x)$ and if $(x-c)$ is a factor of $f(x)$, then $f(c)=0$. Hence, here the function is in the form: $P(x)=(x-(-0.5))(x-2)(x-3)=ax^3 - 4.5 ax^2 + 3.5a x + 3a$ We know that the constant coefficient is $12$. Hence, we can write: $3a=12$ $a=4$ Thus, we have: $P(x)=4x^3 - 18 x^2 + 14 x + 12$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.