College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises - Page 267: 9

Answer

$f(0)=6$ $f(2)=2$ $f(-2)=18$ $f(a)=a^{2}-4a+6$ $f(-a)=a^{2}+4a+6$ $f(x+1)=x^{2}-2x+3$ $f(2x)=4x^{2}-8x+6$

Work Step by Step

$f(x)=x^{2}-4x+6$ Plug in x values into g(x) $f(0)=(0)^{2}-4(0)+6=6$ $f(2)=(2)^{2}-4(2)+6=2$ $f(-2)=(-2)^{2}-4(-2)+6=18$ $f(a)=a^{2}-4a+6$ $f(-a)=(-a)^{2}-4(-a)+6=a^{2}+4a+6$ $f(x+1)=(x+1)^{2}-4(x+1)+6=x^{2}+2x+1-4x-4+6=x^{2}-2x+3$ $f(2x)=(2x)^{2}-4(2x)+6=4x^{2}-8x+6$
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