Answer
See below.
Work Step by Step
$(f\circ g)(x)=f(g(x))=f(x-1)=-(x-1)^2-2(x-1)+1=-x^2+2x-1-2x+2+1=-x^2+2$
$(g\circ f)(x)=g(f(x))=g(-x^2-2x+1)=(-x^2-2x+1)-1=-x^2-2x$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Summary, Review, and Test - Cumulative Review Exercises (Chapters 1-8) - Page 792: 30
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
