College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.5 - Page 285: 155

Answer

$\frac{2x}{3-x}$

Work Step by Step

$\dfrac{2}{\frac{3}{x}-1}=\dfrac{2}{\frac{3}{x}-\frac{x}{x}}=\dfrac{2}{\frac{3-x}{x}}=2\cdot\frac{x}{3-x}=\frac{2x}{3-x}$
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