Answer
$\frac{2x}{3-x}$
Work Step by Step
$\dfrac{2}{\frac{3}{x}-1}=\dfrac{2}{\frac{3}{x}-\frac{x}{x}}=\dfrac{2}{\frac{3-x}{x}}=2\cdot\frac{x}{3-x}=\frac{2x}{3-x}$
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