College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.3 - Geometry Essentials - R.3 Assess Your Understanding - Page 37: 52

Answer

Area of deck = big circle (pool + deck) - small circle (pool) = 69$\pi$$ft^{2}$ Amount of fence required to enclose the fence = circumference of big circle (pool + deck) = 26$\pi$ft

Work Step by Step

What is the area of the deck? We can see that the area of the deck = area of big circle (pool + deck) - area of small circle (pool) SOLVING FOR THE AREA OF THE SMALL CIRCLE: Recall that the area of a circle is equal to $\pi$$r^{2}$, where r is the radius of the circle The diameter of the small circle is 20ft as shown in the diagram. We can divide the diameter of the circle by 2 to get the radius. Radius of little circle = 20ft $\div$ 2 = 10ft Know that we know the radius, we can find the area Area of little circle = $\pi$$r^{2}$ = $\pi$$(10ft)^{2}$ = 100$\pi$$ft^{2}$ The area of the small circle is 100$\pi$$ft^{2}$ SOLVING FOR THE AREA OF THE BIG CIRCLE: The radius of the big circle is equal to the radius of the small circle + the width of the deck We know that the deck has a width of 3ft We also know from before that the radius of the small circle is equal to 10ft radius of big circle = radius of small circle + width of deck = 10ft + 3ft = 13ft Now that we know the radius, we can substitute the radius into the equation Area = $\pi$$r^{2}$ Area of big circle = $\pi$$r^{2}$ = $\pi$$(13ft)^{2}$ = 169$\pi$$ft^{2}$ The area of the big circle is 169$\pi$$ft^{2}$ SOLVING FOR THE AREA OF THE DECK Area of deck = area of big circle (pool + deck) - area of small circle (pool) = 169$\pi$$ft^{2}$ - 100$\pi$$ft^{2}$ = 69$\pi$$ft^{2}$ The area of the deck is 69$\pi$$ft^{2}$ How much fence is required to enclose the deck? The amount of fence required to enclose the deck is equal to the circumference of the big circle Recall that the circumference of a circle is equal to $\pi$d or 2$\pi$r, where r is the radius and d is the diameter Since we already know from before that the radius of the big circle is 13$\pi$, we can plug this number into the equation for circumference = 2$\pi$r Circumference of big circle = 2$\pi$r = (2$\pi$)(13ft) = 26$\pi$ The amount of fence required to enclose the deck is 26$\pi$ft
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.