Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.7 - Factoring Special Products - Monitoring Progress - Page 399: 11

Answer

$9(z+2)^2$.

Work Step by Step

The given polynomial is $=9z^2+36z+36$ Factor out $9$. $=9(z^2+4z+4)$ Write the the polynomial as $a^2+2ab+b^2$. $=9(z^2+2(z)(2)+2^2)$. Use perfect square trinomial pattern $a^2+2ab+b^2=(a+b)^2$. We have $a=z$ and $b=2$. $=9(z+2)^2$. Hence, the factor of the given polynomial is $9(z+2)^2$.
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