Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.7 - Factoring Special Products - Monitoring Progress - Page 398: 3

Answer

$(3n+4)(3n-4)$.

Work Step by Step

The given polynomial is $=9n^2-16$ Write as square terms. $=(3n)^2-4^2$ Use special formula $a^2-b^2=(a+b)(a-b)$. $a=3n$ and $b=4$ $=(3n+4)(3n-4)$.
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