Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.7 - Factoring Special Products - Exercises - Page 401: 35

Answer

$3(z+3)(z-3)$.

Work Step by Step

The given polynomial is $= 3z^2-27$ Factor out $3$. $= 3(z^2-9)$ Write the the polynomial as $a^2-b^2$. $= 3(z^2-3^2)$ Use difference of two square pattern $a^2-b^2=(a+b)(a-b)$. We have $a=z$ and $b=3$. $= 3(z+3)(z-3)$ Hence, the factor is $3(z+3)(z-3)$.
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