Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Practice - Page 569: 5


y = -3x - 1

Work Step by Step

This problem is asking to graph a parallel line to the line 3x + y = 5, using the point (-1, 2) and to write it in slope-intercept form. The first task is to change the equation to slope-intercept form: (y = mx + b) First subtract both sides by 3x to get y alone. The new equation is: (y = -3x + 5) By using the slope for this line, we can graph our new line. The slope is -3 and this line passes through the y-axis at (0, 5). To find the parallel line we use the point-slope form: (y - yx_{y}1) = m(x - xx_{y}1) (y - 2) = -3(x + 1) **(1 is added here because when you subtract a negative it becomes positive) Next use the distributive property y - 2 = -3x - 3 Then combine like terms (by adding 2 to both sides) The parallel line is y = -3x - 1
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