Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Exercise Set - Page 572: 15

y+8=$\frac{1}{3}$(x+3) 7=$\frac{1}{3}$x-y

(-3;-8),(-6;-9) m=$\frac{-9+8}{-6+3}$=$\frac{-1}{-3}$=$\frac{1}{3}$ slope $\frac{1}{3}$ ,through(-3;-8) y-$y_{1}$=m(x-$x_{1}$) y+8=$\frac{1}{3}$(x+3) y+8=$\frac{1}{3}$x+1 8-1=$\frac{1}{3}$x-y 7=$\frac{1}{3}$x-y