Answer
The solutions are $6$ and $-3$
Work Step by Step
First we factor:
$x^{2}-3x-18=0$
$(x-6)(x+3)=0$
Then we apply the zero-factor property:
$x-6=0$ or $x+3=0$
$x=6$ or $x=-3$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Practice - Page 454: 4
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