## Algebra: A Combined Approach (4th Edition)

$True.$
We can check our answer: (y + 2)(y + 4) = $y^{2}$ + 4y + 2y + 2(4) = $y^{2}$ + 6y + 8 and (y + 4)(y + 2) = = $y^{2}$ + 2y + 4y + 4(2) = $y^{2}$ + 6y + 8. Thus switching (y + 2) and (y + 4) will yield the same result. Thus we can write the factorization (y + 2)(y + 4) as (y + 4)(y + 2).