Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.5 Apply the Law of Sines - 13.5 Exercises - Mixed Review - Page 888: 58



Work Step by Step

Simplifying the expression by cancelling terms in the numerator and the denominator, we find: $$\frac{3\left(x^2-3\right)\left(x+7\right)}{\left(x-1\right)\left(6x^2-18\right)} \\ \frac{3\left(x^2-3\right)\left(x+7\right)}{\left(x-1\right)\cdot \:6\left(x^2-3\right)} \\ \frac{x+7}{2\left(x-1\right)}$$
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