Answer
$$\frac{x^2}{4y^2}$$
Work Step by Step
Simplifying the expression by cancelling terms in the numerator and the denominator, we find:
$$\frac{5x^5xy}{x^3y\cdot \:20xy^2}\\ \frac{5x^5}{x^3\cdot \:20y^2} \\ \frac{x^{5-3}}{4y^2} \\ \frac{x^2}{4y^2}$$
