Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.5 Apply the Law of Sines - 13.5 Exercises - Mixed Review - Page 888: 51

Answer

$$-5\cdot \:2^{\frac{1}{3}}$$

Work Step by Step

Simplifying the expression using the rules of exponents, we find: $$ 5\cdot \:250^{\frac{1}{3}}-10\cdot \:54^{\frac{1}{3}} \\ 25\cdot \:2^{\frac{1}{3}}-30\cdot \:2^{\frac{1}{3}} \\ -5\cdot \:2^{\frac{1}{3}}$$
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