Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - Get Ready - Page 411: 19

Answer

$1$

Work Step by Step

We start with the given expression: $[(5+2)^{2}-7]\div[(3+3)^{2}+6]$ According to Order of Operations we must add inside the innermost grouping symbols, then multiply the quantitie by the exponent, next we can add or subtract inside the grouping symbols and finally we can divide the two quantities Addition inside parentheses: $(7^{2}-7)\div(6^{2}+6)$ Now multiply by the power of two: $(49-7)\div(36+6)$ Next add inside parentheses: $(42)\div(42)$ Division of the quantities: $1$
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