Answer
$e^{-\frac{\pi}{2}}$
$-1$
Work Step by Step
Start by noticing that j can be written as
${e^{j\frac{\pi}{2}}} ^j = e^{j^2 \frac{\pi}{2}} = e^{-\frac{\pi}{2}}$
$e^{j\pi} = cos(\pi) + jsin(\pi) = -1 $
Fundamentals of Electrical Engineering
by Rizzoni, Giorgio
Published by
McGraw-Hill Education
ISBN 10:
0073380377
ISBN 13:
978-0-07338-037-7
Chapter 4 - AC Network Analysis - Part 1 Circuits - Homework Problems - Page 171: 4.41
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