A 55 kg block of metal has an original temperature of 15.0°C and 0.45 J/g∙°C. What will be the final temperature of this metal if 450 J of heat energy are added?

We know that the heat energy (Q) that supplied to the body will be used to increase the temperature of the body according to the relation

Q = mcΔt

where, Q = 450 J

mass of the body (m) = 55 kg

specific heat (c) = 0.45 J/g.°C = 0.45 x 1000 J/ kg.°C = 4500 J/ kg.°C

and Δt = increase in temperature = final temperature - initial temperature = t - 15, ( t = finaltemperature)

Therefore, 450 = 55 x 4500 x (t - 15)

or, t - 15 = 450/(55x4500)

or, t - 15 = 1/(55x10)

or, t - 15 = 1/550

or, t - 15 = 0.00182

or, t = 0.00182 + 15

or, t = 15.00182

So the final temperature of the body will be 15.00182 °C.