University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 296: 9.33

Answer

$I = 0.193~kg~m/s$

Work Step by Step

Let $m_r$ be the mass along the rim and let $m_s$ be the mass of one spoke. $I = m_r~r^2 + (8\times \frac{1}{3}m_s~r^2)$ $I = (1.40~kg)(0.300~m)^2 + (8\times \frac{1}{3}(0.280~kg)(0.300~m)^2)$ $I = 0.193~kg~m/s$
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