University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 295: 9.14

Answer

$\alpha = 23.3~rad/s^2$ $\theta = 420~rad$

Work Step by Step

$\omega = \omega_0+\alpha ~t$ $\alpha = \frac{\omega - \omega_0}{t}$ $\alpha = \frac{140~rad/s - 0}{6.00~s}$ $\alpha = 23.3~rad/s^2$ $\theta = \frac{1}{2}\alpha ~t^2$ $\theta = \frac{1}{2}(\frac{140~rad/s}{6.00~s})(6.00~s)^2$ $\theta = 420~rad$
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