University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 294: 9.1

Answer

(a) $\theta = 0.60~rad$ $\theta = 34.4^{\circ}$ (b) r = 6.27 cm (c) arc = 1.05 m

Work Step by Step

(a) $\theta~ (2.50~m) = 1.50~m$ $\theta = \frac{1.50~m}{2.50~m}$ $\theta = 0.60~rad$ $\theta = (0.60~rad)(\frac{180^{\circ}}{\pi ~rad})$ $\theta = 34.4^{\circ}$ (b) $\frac{14.0~cm}{\pi ~r}=\frac{128^{\circ}}{180^{\circ}}$ $r = \frac{(14.0~cm)(180^{\circ})}{(\pi)(128^{\circ})}$ $r = 6.27~cm$ (c) $arc = \theta ~r$ $arc = (0.700~rad)(1.50~m)$ $arc = 1.05~m$
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