Answer
The slab moves with a speed of 0.400 m/s relative to the ice.
Work Step by Step
Let the person's mass be $m$. Then the slab's mass is $5m$. We can use conservation of momentum to solve this question. Note that the initial momentum is zero.
$m~v_p + (5m)~v_s = 0$
$v_s = \frac{-m~v_p}{5m}$
$v_s = \frac{-v_p}{5}$
$v_s = \frac{-2.00~m/s}{5}$
$v_s = -0.400~m/s$
The slab moves with a speed of 0.400 m/s relative to the ice.
