University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 8 - Momentum, Impulse, and Collision - Problems - Exercises - Page 265: 8.30

Answer

The mass of the canister is 81.8 kg.

Work Step by Step

We can use conservation of momentum to solve this question. $m_c~v_{c1} + m_a~v_{a1}= m_c~v_{c2} + m_a~v_{a2}$ $m_c~v_{c1} + 0 - m_c~v_{c2} = m_a~v_{a2}$ $m_c = \frac{m_a~v_{a2}}{v_{c1} - v_{c2}}$ $m_c = \frac{(78.4~kg)(2.40~m/s)}{3.50~m/s - 1.20~m/s}$ $m_c = 81.8~kg$ The mass of the canister is 81.8 kg.
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