Answer
The average force on the ball is 563 N.
The effect of the ball's weight is not significant.
Work Step by Step
$F~t = \Delta p$
$F~t = m \Delta v$
$F = \frac{m \Delta v}{t}$
$F = \frac{(0.0450~kg)(25.0~m/s)}{0.00200~s}$
$F = 563~N$
The average force on the ball is 563 N
The weight of the ball is $(0.0450~kg)(9.80~m/s^2)$, which is 0.441 N. Since the weight is negligible compared to the average force applied to the ball, the effect of the ball's weight is not significant.
