University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 7 - Potential Energy and Energy Conservation - Problems - Exercises - Page 230: 7.18

Answer

(a) $U_0 = 2.16~J$ (b) The 25-g pebble could go up to a height of 8.8 meters. (c) We ignored air resistance in solving this question.

Work Step by Step

The initial potential energy stored in the slingshot will be equal to the potential energy of the pebble at maximum height. (a) $U_0 = mgh = (0.010~kg)(9.80~m/s^2)(22.0~m)$ $U_0 = 2.16~J$ (b) $mgh = U_0$ $h = \frac{U_0}{mg} = \frac{2.16~J}{(0.025~kg)(9.80~m/s^2)}$ $h = 8.8~m$ The 25-g pebble could go up to a height of 8.8 meters. (c) We ignored air resistance in solving this question.
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