University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 6 - Work and Kinetic Energy - Problems - Exercises - Page 200: 6.85

Answer

(a) $W = 1.10\times 10^5~J$ (b) $W = 1.30\times 10^5~J$ (c) $P = 4000~W$

Work Step by Step

(a) $W = mgh$ $W = (800~kg)(9.80~m/s^2)(14.0~m)$ $W = 1.10\times 10^5~J$ (b) $W = \frac{1}{2}mv^2$ $W = \frac{1}{2}(800~kg)(18.0~m/s)^2$ $W = 1.30\times 10^5~J$ (c) $P = \frac{W_{tot}}{60~s}$ $P = \frac{1.10\times 10^5~J+1.30\times 10^5~J}{60~s}$ $P = 4000~W$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.